Sorry about the long delay; I got encouraged into preparing for and then running to be moderator of a largish forum. ... and then once I was elected, I had to learn the ropes Still learning, really. Anyway, I hope to get myself back up to speed on your problem and hopefully show you something useful.

Hmm. I may have something. It looks like it's possible to have a nomogram for ADF/OG/FG and ADF/B0/B1 with a common ADF scale, a shared scale (I think right down to the tick-mark labels, but I need to double check that) parallel to it for two of the variables, and then the remaining variables on two...

With the image -- I don't understand why my image doesn't show up in my post then, since I think I did pretty much exactly that.

I've been playing with a determinant with B0,B1,OG,FG,ADF in it. I keep getting sort of close to something nice -- but it's tricky

[quote="kloekwil"] When trying to align the og-line with the B0 line the og line ends up somewhere below the B1-line...[/quote] Hmm, it's easy enough to do by hand: [img]http://i.imgur.com/DQvK14L.jpg [/img] so I'm certain Pynomo can do it ... Hey, how do you get the images to show up in t...

Sorry to have missed all the excitement.

I'll try to have a look to see what I can do with B1.

An ADF/OG/FG one can be done with 3 parallel scales, which means you could do it with a "slide rule" device.

(You may not be able to get all 5 variables on a single scale.)

Just had a quick read through - that's a nice article!

I have saved to reread it again more carefully.

This relates to the post I made a while back on a nomogram for V = 12h³ −6ah² +ha² I was playing with it just recently and got it into a form (with some constant factors removed, since they can be incorporated into the variables they multiply) like this: (z/x)³ - 1 = [(y/x)-1]³ Which perhaps might h...

[quote="cjltuk"]I don't know how to offer this back to the community. Can anyone tell me?[/quote] Leif would probably be better placed to answer this but I think the two possible routes are either to see if Leif wants to incorporate your code or to fork the code. If it was on Github you co...

This blog entry has some discussion and a number of links relating to nomographical topics:

http://headinside.blogspot.com.au/2014/ ... abola.html

I thought the tin monkey was pretty sweet.

Looks like the account bruce741 is a spammer. His post here: http://nomography.org/phpBB3/viewtopic.php?t=28#p284 just repeats some of a previous post (so if you're not paying close attention, it *looks* legitimate) and then links to a commercial site (to do with leather jackets) in the signature So...

Thanks, Jason. The first one is nifty. The burns one doesn't seem to be free- free access - I can see the abstract but the full text and the pdf tabs bring up a 'log in or register' window. Is it free access for registering? If so, do you know what information they seek? The third one (BJS) gives me...

Thanks Joe, I'm interested in the material relating to such 'usage error' in nomography, from the point of view of measuring and reducing it, and also in the sense that it gives a bound on the accuracy with which there's any point in approximating a relationship with a nomographic relationship. In p...

[quote="NomoDave"]Hi Glen Please could you recommend a good reference or two to get me started on understanding this technique (I've got a rapidly growing library of old nomography books, but not sure which gives the best introduction to this topic for a beginner). Dave[/quote] Dave, besid...

Yeah, while the functions U1 and U2 define a hyperbola for the curve of u, for a fair bit of the range of u it doesn't curve much, being almost straight.

Looking at my own explanation for what I did again, I notice that the RHS of y = mn - n + mn^2 can be split up in two ways - (1) ... (n^2+n) m - n OR (2) ... (m-1)n + mn^2 Both can be put into a determinant; both yield a straight scale for m (and hence for w) and a curved scale for n (and hence for ...